Originally posted by audiobomber I know how to calculate the resulting macro ratio with a Raynox on a lens when focussed at infinity. Is there a way to tell what kind of magnification adding a diopter will bring at minimum focus? (Obviously not valid for an internal-focus lens).
Magnification is the size of the image on the sensor divided by the actual size of the subject.
With just the original lens objects in focus at infinity have zero size on the sensor, hence zero magnification. As you turn the focusing ring subjects closer than infinity are in focus, hence there is a magnification associated with how close the original lens is to the subject in focus.
Sometimes the original lens' specification gives its maximum magnification ratio, like 1:4 or you can measure it by taking a photo of a ruler.
The minimum magnification of a closeup lens & main lens combo is when the main lens is focused at infinity; call it minimum_close_up_mag.
Minimum_close_up_mag=Original_focal_length/Close_up_focal_length
If the original lens is focused closer than infinity it has an original mag & the equation for total magnification is:
Total_mag=original_mag+minimum_close_up_mag(1+original_mag)
Say you start with a magnification of .25 & use a 2X closeup lens combo, The final magnification is
Total_mag=0.25+2(1+0.25)=2.75
Dave
PS your 16-45 has a maximum magnification of 0.25X at 45mm (according to
http://www.dpreview.com/lensreviews/pentax_16-45_4_p15/).
Let's use a Raynox 250 with it; The minimum mag with the Raynox 250 on the 16-45 at 45mm is (I recall you said the Raynox' actual focal length is 109mm):
Min_mag=45/109=0.41X
The maximum mag is:
Max_mag=0.25+0.41(1+0.25) = 0.76X
Last edited by newarts; 07-13-2009 at 12:11 PM.