Say one is displaying a Pentax K-x image at 300 mm width. The K-x's sensor is 23.5mm wide, so the sensor's image is enlarged by a factor of 300/23.5=12.8x.
The viewer's resolution is about 0.25mm on the display which corresponds to a spot size on the sensor of 0.25mm/12.8x=19.6 micrometers.
At a macro magnification of 1:1 the diffraction spot size on the sensor is related to the f-stop by:
19.6=(4/3)f(1+1), or f = 7.3
based on Airy Disk diameter for greenish light including magnification effect
This means that above f:7.3 the diffraction spot size on the display is larger that the viewer's resolution, hence the image loses sharpness.
Notice that the sensor's pixel count did not enter the discussion because the display size was fixed and the sensor's pixel count was more than needed to fill the display at the desired resolution.
Sensor pixel pitch would be controlling if we had specified a 100% crop for example - in that case the diffraction spot size would be compared to the sensor pixel size, not the display pixel size since for a 100% crop each sensor pixel is mapped to each display pixel. The K-x's pixel size is about 5.5 micrometers so a 1:1 macro's diffraction spot size equals the pixel size at about f:2!
Dave
PS The above is a simplified version of what's going on because of details of displaying digital images with digital devices.
More stringent display resolutions (like for a high quality print) would have required a smaller f-stop.
Last edited by newarts; 10-15-2010 at 04:54 AM.