Originally posted by falconeye I stopped debating this, but for the record of war reporters out there ...
You said a 70-200/4 lens projects as many photons onto the entire surface of an FF sensor as a 35-100/4 lens projects onto the entire surface of a FourThirds sensor.
While I said a 70-200/4 lens projects as many photons onto the entire surface of an FF sensor as a 35-100/2 lens projects onto the entire surface of a FourThirds sensor (which is my statement you just quoted and you insist to be wrong).
No I DID NOT SAY THAT. You seem to enjoy saying things that I did not say.
I said that the SAME LENS for any given 10mm x 10mm square, whether it's a full frame or 4/3, the same number of photons will fall onto the same area.
Here is the proof of what I said:
Originally posted by dnas The light intensity is measured as light per unit area. This means that the light falling on, say, a 10mm x 10mm area is the same regardless of sensor area, for a given F-stop number and external light intensity. So if an F2.8 lens, wide open, exposes that 10mm x 10mm area of a FF sensor or a 4/3 sensor, the resulting area has exactly the same light intensity & exposure.
What you say above it correct about the number of photons, but there is one thing you haven't taken into account: Standard calibration.
ANY camera with any sensor must be calibrated. This takes a standard (in this case the amount of light) and calibrates the sensor to this standard. So if you have a Canon 5D (FF, 12M pixel) or a 450D (APS-C, 12M pixel), and you use a Canon 200mm 2.8 L (FF), then it will work with both cameras. And both cameras WILL KNOW that wide open, the lens is F2.8 This is fact.
According to your logic, the lens on the 450D would need to be 125mm F1.75, in order for the SAME number of photons to fall on the whole smaller APS-C sensor..... and you'd be right.
HOWEVER, the sensor is NOT CALIBRATED by the number of photons falling on the WHOLE SENSOR, it is calibrated by the number of photons
per unit area. This is TRUE, because the same lens (Canon 200mm 2.8 L, FF) must work on both the Canon 5D (FF, 12M pixel) and a 450D (APS-C, 12M pixel).
The calibration occurs in the sensitivity of the sensor. Because there are only 25% the number of photons hitting each pixel on the APS-C sensor, the gain on the sensor (sensitivity) is boosted. So at the standardized 100 ISO, the light cast onto each sensor by the Canon 200mm 2.8 L will yield the same result so far as exposure goes, on the final image. If it was calibrated to total number of photons on the WHOLE sensor, the 450D result would be darker by two stops.
That is why this statement is correct:
"It is important to note that neither the light gathering ability of the lens, nor any of its traits are actually affected: a 50mm f2 lens on a 4/3rds body has the same f-stop as a 50mm lens on a 35mm camera. But the 4/3rds sensor only records the equivalent field of view of a 100mm lens."
From here:
Four Thirds - Camerapedia.org
That's why your statement is incorrect:
Originally posted by falconeye And for equal light gathering capabilities, they need half the f-stop figure.