Let's try it in simple words with as little scientific language as possible with a simple simulation.
Remember that "dynamic range" in photography is the size of the spread between the brightest bits of information in a photo and the darkest bits.
Dynamic range - Wikipedia
What are the limiting factors at each end?
- bright end:the sensor pixels at some point can not register more photons and are "full". The image area now is pure white and no more detail can be recovered.
- dark: the (mostly random) noise in the really dark areas can grow so much that you are unable to get meaningful image subject information. The nerds call this signal-to-noise-ratio ("SNR") being very low. At SNR 1 (=1:1) it means you have as much good image information ("signal") as you have crappy noise.
So the space between clipping highlights and massive noise in the shadows is dynamic range.
Comparison setup to be realistic:
- Imagine the exact same exposure parameters to be used for both a large and a small sensor camera.
For example it could be ISO 100, shutter 1 sec., aperture F/8 (not "equivalent") on both cameras. - we ignore DoF for this question for now as it is about maximum dynamic range only
- Imagine shooting the absolute black subject. We do not need to worry about lenses here.
- To make the point very visually easy here, let us assume a major size difference between the sensors. Crop factor 8.
- Imagine both sensor have the exact same technology level and the exact same pixel size. So the individual pixel is technically the same.
This means the pixels will clip to white at exactly the same brightness level. So the upper end of the dynamic range is the same for both sensors.
Look at what the small sensor has registered:
Hm. You might barely notice some little noise here.
Now let us take a look at what the large sensor has registered:
It is 8 times as wide and 8 times as high as the smaller sensor. To simulate the same technology, same exposure I just created a 8x8 mosaic from the smaller sensor. So both sensors work absolutely identical.
Still looking only very mildly noisy.
If you look at the files in 100% screen mode you will see proof that the noise is exactly the same on both per area (!).
User style option A)
And
if you are a person who typically watches images as I have presented the two pieces above - with the
display sizes as different as the sensor sizes - then this is it for you. Same dynamic range for both. No need to worry about "equivalency".
User style option B)
But actually this is not how the vast majority of people watch images. They typically
look at both images on the same electronic device (screen) or in the same print size.
The latter obviously means you have to enlarge the crop 8 sensor image 8 times more. And this has quite an effect:
Left side: large sensor, right side small sensor
Squint your eyes a little bit and look at both images. You will see the noise on the crop 8 sensor is much worse.
This does show that the magnification path from sensor size to display size actually changes the perceived noise.
Magnifying an image means raising the noise level. This in itself means lowering the dynamic range by magnification.
Because larger sensors do need less magnification from sensor to display sizes the
perceived noise is lower and the dynamic range higher with regards to the
displayed image - while it stays the same per sensor area.
Yes, even while the small sensor image has the exact same level of noise
per sensor area, the magnification from sensor to display makes it worse for the watching person. It's all about magnification.
Enjoy the discussions.