Originally posted by UncleVanya I'm confused. I thought a 1degree spot meter was an absolute measurement covering 1 degree. The FOV of the spot meter is 1 degree - where did 37 degrees enter the picture?
Put another way. If I use a lensatic compass or a more accurate version and mark two points in the distance 1 degree apart the diameter of the area the meter covers should roughly be the same - right?
Thus a lens with a fov of X * 0.15 = 1 will give the answer to the fov needed of the lens to match the original question. (X = 1/.015 = 6.66 degrees) which is a very large telephoto on 6x7.
Thank´s for the help on the math. Your math bit corresponds with my illustration. Hand held 1° spot meter is 1°, but at some point (6.66°=6X7 600mm/6.7°) the image is enlarged so much, that the 15° spot on the AE finder meter equals the FOV as seen in the spot meter, that has a normal lens. The 37° is the degree of a ‘normal‘ (105 mm) on 6X7 and the hand held Pentax spot meters have a ‘normal‘ lens (as far I know?)—it could also be a 90 mm/42.5°?
---------- Post added 1st Feb 2017 at 09:32 AM ----------
Originally posted by Digitalis It is a shame Pentax didn't incorporate OTF metering in the Pentax 67, there is a surprising amount of empty space around the mirror box in that chassis.
Im considering using my LX with a tele for it´s brilliant meter.
---------- Post added 1st Feb 2017 at 09:36 AM ----------
Originally posted by Silent Street What is the reading with the Minolta meter?
I didn´t have the Minolta last year and I don´t think it would be precise enough on that distance to subject (200 meters in a restricted area, can´t enter—there is one other view to the nest and it is even more difficult)?
---------- Post added 1st Feb 2017 at 09:55 AM ----------
... this is the subject—not the surrounding trees:
Last edited by jt_cph_dk; 02-01-2017 at 03:36 AM.