Originally posted by OregonJim Wrong. You have to REDUCE the image to see it onscreen, unless you happen to have a 10 or 14MP monitor (I don't think they exist yet).
Magnification in this context is more literal than that - it refers to physical dimensions. An APS-C sensor is 16x24mm (roughly). If you want to see the image larger than that, you are magnifying it, and hence, amplifying the effect of camera shake. It has nothing to do with number of pixels; the effect is just as real when using APS-C *film* cameras.
This also has an effect on DOF calculations, BTW.
Quote: Magnification in the context of thread means enlarging a crop-sensor image to the equivalent size of a full-frame sensor image. E.G, to make 8x10 prints from both (assuming resolution is identical), the crop-sensor image must be enlarged 1.5 time the FF image in order for the images to look "similar" (same field of view).
Precisely. And because the APS-C image requires more magnification, it also requires that much faster a shutter speed in order to control camera shake when using any given lens.
Another way of seeing the exact same phenomenon: you need a faster shutter speed to make an acceptably sharp 8x10" enlargement of a given negative than to make an acceptably sharp 4x6", at least if you plan on viewing both from the same distance. Of course, normally, you might vidw the 8x10" from a somewhat greater distance, nullifying the need for greater sharpness to some extent. But then if you cropped the 8x10" enlargement to 4x6", you'd have an exact analogue of the situation with an APS-C camera.