Originally posted by pcarfan LOL, No.
Anytime high iso and exposing to the right comes to play, this always crops up.
The consensus is that proper exposure is more important than the lowest iso and then pulling out the detail.
So what is the point to take the snap to the right with high iso if you can take at lower iso and EV to the right - unless you can not....(to long shutter?) besides you have actually showed the pictures at about iso 800 if you really, during the processing, lowered exposure.
Originally posted by pcarfan Also, think of it this way. +EV is totally arbitrary. If I used the spot metering, then it would meter off the darker areas and I may have to dial in -EV. So, EV compensation is totally dependent on my choice of metering. In the extreme, the spot metering can be run to the extreme by either getting the meter reading from the brightest part of the image or the darkest.
So, only thing we can do is to expose by the histogram. This is what I kept mentioning as having no clippings. So, +2 EV is irrelevant, what is important is whether the exposure renders the ideal histogram.
Again, why to take the snap with higher iso if you can do it at lower using histogram - only benefit i can see out of this thread is advice: when one take the photo at high iso one need to set the exposure as much as possible to the right using histogram as a measuring device
Originally posted by pcarfan So, if I had 0 EV with the chosen metering, then it would mean underexposing the scene by two stops and using iso 800. This will require +2EV in post processing to get the ideal exposure. It is always better to use a higher iso to get proper exposure which will give the least amount of noise than to underexpose and recover which will show more noise. So, using 800 will be the wrong choice.
and then again - who makes you set 0 exposure at iso 800? Sorry if i didn't get something - you can call me bone-head, but please explain.... if the conditions makes you to set iso3200, 1/5s, f4, EV+2 why not to set it at iso 800 and EV0 if you at both cases would obtain similar histogram on the final picture? Am i wrong?