Originally posted by asdf When you zoom in with the kit lens to 55, the aperture wide open is f/5.6, which means the viewfinder is 2^4 = 16 times dimmer than with FA 50 f/1.4.
is-it 2^4 or 4^2 ?
in this case both are the same, 16 times less light
does it mean every stop on the aperture ring is double/half the light of the previous stop? so from F1.4 to 5.6 to go through F1.8, 2.8, 4, 5.6 resulting in 4 steps which is 2^4=16 or 4^2 I am confused, please someone correct or confirms my understanding (as I understand, the amount is a square relationship every step)