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Forum: Pentax K-1 & K-1 II
09-20-2016, 08:00 AM
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If the sensor is exposed to light, it's constantly generating a current that accumulates in the photosite pixels. The EFCS has to drain that charge so that the photosite has zero charge at the beginning of the exposure. But such circuits always have some resistance which means that the pixel begins the exposure with some residual charge in proportion to the pre-shutter intensity of light.
In photographic terms, the sensor will have a faint ghost of a image of the light from before the official shutter time.
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